(x^2+10x+2)=0

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Solution for (x^2+10x+2)=0 equation:


Simplifying
(x2 + 10x + 2) = 0

Reorder the terms:
(2 + 10x + x2) = 0

Remove parenthesis around (2 + 10x + x2)
2 + 10x + x2 = 0

Solving
2 + 10x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + 10x + -2 + x2 = 0 + -2

Reorder the terms:
2 + -2 + 10x + x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 10x + x2 = 0 + -2
10x + x2 = 0 + -2

Combine like terms: 0 + -2 = -2
10x + x2 = -2

The x term is 10x.  Take half its coefficient (5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
10x + 25 + x2 = -2 + 25

Reorder the terms:
25 + 10x + x2 = -2 + 25

Combine like terms: -2 + 25 = 23
25 + 10x + x2 = 23

Factor a perfect square on the left side:
(x + 5)(x + 5) = 23

Calculate the square root of the right side: 4.795831523

Break this problem into two subproblems by setting 
(x + 5) equal to 4.795831523 and -4.795831523.

Subproblem 1

x + 5 = 4.795831523 Simplifying x + 5 = 4.795831523 Reorder the terms: 5 + x = 4.795831523 Solving 5 + x = 4.795831523 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = 4.795831523 + -5 Combine like terms: 5 + -5 = 0 0 + x = 4.795831523 + -5 x = 4.795831523 + -5 Combine like terms: 4.795831523 + -5 = -0.204168477 x = -0.204168477 Simplifying x = -0.204168477

Subproblem 2

x + 5 = -4.795831523 Simplifying x + 5 = -4.795831523 Reorder the terms: 5 + x = -4.795831523 Solving 5 + x = -4.795831523 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + x = -4.795831523 + -5 Combine like terms: 5 + -5 = 0 0 + x = -4.795831523 + -5 x = -4.795831523 + -5 Combine like terms: -4.795831523 + -5 = -9.795831523 x = -9.795831523 Simplifying x = -9.795831523

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-0.204168477, -9.795831523}

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